(2x+103)=(7x+68)

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Solution for (2x+103)=(7x+68) equation: 



(2x+103)=(7x+68)

We move all terms to the left:

(2x+103)-((7x+68))=0

We get rid of parentheses

2x-((7x+68))+103=0



We calculate terms in parentheses: -((7x+68)), so:

(7x+68)

We get rid of parentheses

7x+68

Back to the equation:

-(7x+68)



We get rid of parentheses

2x-7x-68+103=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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