(2x+10x)(2x-10x)=0

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Solution for (2x+10x)(2x-10x)=0 equation: 



(2x+10x)(2x-10x)=0

We add all the numbers together, and all the variables

(+12x)(-8x)=0

We multiply parentheses ..

(-96x^2)=0

We get rid of parentheses

-96x^2=0

a = -96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-96)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-192}=0$

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