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(2x+11)(3x-7)=0
We multiply parentheses ..
(+6x^2-14x+33x-77)=0
We get rid of parentheses
6x^2-14x+33x-77=0
We add all the numbers together, and all the variables
6x^2+19x-77=0
a = 6; b = 19; c = -77;
Δ = b2-4ac
Δ = 192-4·6·(-77)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-47}{2*6}=\frac{-66}{12} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+47}{2*6}=\frac{28}{12} =2+1/3 $
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