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(2x+11)(5x-18)=0
We multiply parentheses ..
(+10x^2-36x+55x-198)=0
We get rid of parentheses
10x^2-36x+55x-198=0
We add all the numbers together, and all the variables
10x^2+19x-198=0
a = 10; b = 19; c = -198;
Δ = b2-4ac
Δ = 192-4·10·(-198)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-91}{2*10}=\frac{-110}{20} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+91}{2*10}=\frac{72}{20} =3+3/5 $
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