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(2x+12)(2x+10)=240
We move all terms to the left:
(2x+12)(2x+10)-(240)=0
We multiply parentheses ..
(+4x^2+20x+24x+120)-240=0
We get rid of parentheses
4x^2+20x+24x+120-240=0
We add all the numbers together, and all the variables
4x^2+44x-120=0
a = 4; b = 44; c = -120;
Δ = b2-4ac
Δ = 442-4·4·(-120)
Δ = 3856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3856}=\sqrt{16*241}=\sqrt{16}*\sqrt{241}=4\sqrt{241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{241}}{2*4}=\frac{-44-4\sqrt{241}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{241}}{2*4}=\frac{-44+4\sqrt{241}}{8} $
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