(2x+12)(2x+8)=140

Solution for (2x+12)(2x+8)=140 equation:

(2x+12)(2x+8)=140

We move all terms to the left:

(2x+12)(2x+8)-(140)=0

We multiply parentheses ..

(+4x^2+16x+24x+96)-140=0

We get rid of parentheses

4x^2+16x+24x+96-140=0

We add all the numbers together, and all the variables

4x^2+40x-44=0

a = 4; b = 40; c = -44;
Δ = b2-4ac
Δ = 402-4·4·(-44)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-48}{2*4}=\frac{-88}{8}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+48}{2*4}=\frac{8}{8}
=1
$