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(2x+12)(2x+8)=x
We move all terms to the left:
(2x+12)(2x+8)-(x)=0
We add all the numbers together, and all the variables
-1x+(2x+12)(2x+8)=0
We multiply parentheses ..
(+4x^2+16x+24x+96)-1x=0
We get rid of parentheses
4x^2+16x+24x-1x+96=0
We add all the numbers together, and all the variables
4x^2+39x+96=0
a = 4; b = 39; c = +96;
Δ = b2-4ac
Δ = 392-4·4·96
Δ = -15
Delta is less than zero, so there is no solution for the equation
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