(2x+12)(7x+42)=0,

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Solution for (2x+12)(7x+42)=0, equation: 



(2x+12)(7x+42)=0.

We multiply parentheses ..

(+14x^2+84x+84x+504)=0

We get rid of parentheses

14x^2+84x+84x+504=0

We add all the numbers together, and all the variables

14x^2+168x+504=0

a = 14; b = 168; c = +504;
Δ = b2-4ac
Δ = 1682-4·14·504
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-168}{28}=-6$

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