(2x+12)(8x+4)=0

Solution for (2x+12)(8x+4)=0 equation:

(2x+12)(8x+4)=0

We multiply parentheses ..

(+16x^2+8x+96x+48)=0

We get rid of parentheses

16x^2+8x+96x+48=0

We add all the numbers together, and all the variables

16x^2+104x+48=0

a = 16; b = 104; c = +48;
Δ = b2-4ac
Δ = 1042-4·16·48
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(104)-88}{2*16}=\frac{-192}{32}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(104)+88}{2*16}=\frac{-16}{32}
=-1/2
$