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(2x+12)+(2x+4)=64
We move all terms to the left:
(2x+12)+(2x+4)-(64)=0
We get rid of parentheses
2x+2x+12+4-64=0
We add all the numbers together, and all the variables
4x-48=0
We move all terms containing x to the left, all other terms to the right
4x=48
x=48/4
x=12
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