(2x+12)+(7x-10)+(3x+16)=180

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Solution for (2x+12)+(7x-10)+(3x+16)=180 equation: 



(2x+12)+(7x-10)+(3x+16)=180

We move all terms to the left:

(2x+12)+(7x-10)+(3x+16)-(180)=0

We get rid of parentheses

2x+7x+3x+12-10+16-180=0

We add all the numbers together, and all the variables

12x-162=0

We move all terms containing x to the left, all other terms to the right

12x=162

x=162/12

x=13+1/2

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