(2x+12)+(9x-20)+56=180

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Solution for (2x+12)+(9x-20)+56=180 equation: 



(2x+12)+(9x-20)+56=180

We move all terms to the left:

(2x+12)+(9x-20)+56-(180)=0

We add all the numbers together, and all the variables

(2x+12)+(9x-20)-124=0

We get rid of parentheses

2x+9x+12-20-124=0

We add all the numbers together, and all the variables

11x-132=0

We move all terms containing x to the left, all other terms to the right

11x=132

x=132/11

x=12

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