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(2x+12)+1=33
We move all terms to the left:
(2x+12)+1-(33)=0
We add all the numbers together, and all the variables
(2x+12)-32=0
We get rid of parentheses
2x+12-32=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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