(2x+12)+30=(3x+6)

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Solution for (2x+12)+30=(3x+6) equation: 



(2x+12)+30=(3x+6)

We move all terms to the left:

(2x+12)+30-((3x+6))=0

We get rid of parentheses

2x-((3x+6))+12+30=0



We calculate terms in parentheses: -((3x+6)), so:

(3x+6)

We get rid of parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

2x-(3x+6)+42=0

We get rid of parentheses

2x-3x-6+42=0

We add all the numbers together, and all the variables

-1x+36=0

We move all terms containing x to the left, all other terms to the right

-x=-36

x=-36/-1

x=+36

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