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(2x+12)/(5+x)=0
Domain of the equation: (5+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-5
x∈R
(2x+12)/(x+5)=0
We multiply all the terms by the denominator
(2x+12)=0
We get rid of parentheses
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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