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(2x+12)/3=x-5
We move all terms to the left:
(2x+12)/3-(x-5)=0
We get rid of parentheses
(2x+12)/3-x+5=0
We multiply all the terms by the denominator
(2x+12)-x*3+5*3=0
We add all the numbers together, and all the variables
(2x+12)-x*3+15=0
Wy multiply elements
(2x+12)-3x+15=0
We get rid of parentheses
2x-3x+12+15=0
We add all the numbers together, and all the variables
-1x+27=0
We move all terms containing x to the left, all other terms to the right
-x=-27
x=-27/-1
x=+27
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