(2x+12)=(2x-64)

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Solution for (2x+12)=(2x-64) equation: 



(2x+12)=(2x-64)

We move all terms to the left:

(2x+12)-((2x-64))=0

We get rid of parentheses

2x-((2x-64))+12=0



We calculate terms in parentheses: -((2x-64)), so:

(2x-64)

We get rid of parentheses

2x-64

Back to the equation:

-(2x-64)



We get rid of parentheses

2x-2x+64+12=0

We add all the numbers together, and all the variables

76!=0

There is no solution for this equation

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