(2x+12)=(3x+14)+(7x+6)

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Solution for (2x+12)=(3x+14)+(7x+6) equation: 



(2x+12)=(3x+14)+(7x+6)

We move all terms to the left:

(2x+12)-((3x+14)+(7x+6))=0

We get rid of parentheses

2x-((3x+14)+(7x+6))+12=0



We calculate terms in parentheses: -((3x+14)+(7x+6)), so:

(3x+14)+(7x+6)

We get rid of parentheses

3x+7x+14+6

We add all the numbers together, and all the variables

10x+20

Back to the equation:

-(10x+20)



We get rid of parentheses

2x-10x-20+12=0

We add all the numbers together, and all the variables

-8x-8=0

We move all terms containing x to the left, all other terms to the right

-8x=8

x=8/-8

x=-1

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