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(2x+14)(2x+16)=624
We move all terms to the left:
(2x+14)(2x+16)-(624)=0
We multiply parentheses ..
(+4x^2+32x+28x+224)-624=0
We get rid of parentheses
4x^2+32x+28x+224-624=0
We add all the numbers together, and all the variables
4x^2+60x-400=0
a = 4; b = 60; c = -400;
Δ = b2-4ac
Δ = 602-4·4·(-400)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-100}{2*4}=\frac{-160}{8} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+100}{2*4}=\frac{40}{8} =5 $
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