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(2x+14)(2x+18)=0
We multiply parentheses ..
(+4x^2+36x+28x+252)=0
We get rid of parentheses
4x^2+36x+28x+252=0
We add all the numbers together, and all the variables
4x^2+64x+252=0
a = 4; b = 64; c = +252;
Δ = b2-4ac
Δ = 642-4·4·252
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-8}{2*4}=\frac{-72}{8} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+8}{2*4}=\frac{-56}{8} =-7 $
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