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(2x+14)(x+7)=0
We multiply parentheses ..
(+2x^2+14x+14x+98)=0
We get rid of parentheses
2x^2+14x+14x+98=0
We add all the numbers together, and all the variables
2x^2+28x+98=0
a = 2; b = 28; c = +98;
Δ = b2-4ac
Δ = 282-4·2·98
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-28}{4}=-7$
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