(2x+14)5+10=(10-x)2

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Solution for (2x+14)5+10=(10-x)2 equation: 



(2x+14)5+10=(10-x)2

We move all terms to the left:

(2x+14)5+10-((10-x)2)=0

We add all the numbers together, and all the variables

(2x+14)5-((-1x+10)2)+10=0

We multiply parentheses

10x-((-1x+10)2)+70+10=0



We calculate terms in parentheses: -((-1x+10)2), so:

(-1x+10)2

We multiply parentheses

-2x+20

Back to the equation:

-(-2x+20)



We add all the numbers together, and all the variables

10x-(-2x+20)+80=0

We get rid of parentheses

10x+2x-20+80=0

We add all the numbers together, and all the variables

12x+60=0

We move all terms containing x to the left, all other terms to the right

12x=-60

x=-60/12

x=-5

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