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(2x+15)(2x+10)=85
We move all terms to the left:
(2x+15)(2x+10)-(85)=0
We multiply parentheses ..
(+4x^2+20x+30x+150)-85=0
We get rid of parentheses
4x^2+20x+30x+150-85=0
We add all the numbers together, and all the variables
4x^2+50x+65=0
a = 4; b = 50; c = +65;
Δ = b2-4ac
Δ = 502-4·4·65
Δ = 1460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1460}=\sqrt{4*365}=\sqrt{4}*\sqrt{365}=2\sqrt{365}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{365}}{2*4}=\frac{-50-2\sqrt{365}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{365}}{2*4}=\frac{-50+2\sqrt{365}}{8} $
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