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(2x+15)(2x+12)=378
We move all terms to the left:
(2x+15)(2x+12)-(378)=0
We multiply parentheses ..
(+4x^2+24x+30x+180)-378=0
We get rid of parentheses
4x^2+24x+30x+180-378=0
We add all the numbers together, and all the variables
4x^2+54x-198=0
a = 4; b = 54; c = -198;
Δ = b2-4ac
Δ = 542-4·4·(-198)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-78}{2*4}=\frac{-132}{8} =-16+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+78}{2*4}=\frac{24}{8} =3 $
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