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(2x+15)(3x-15)=0
We multiply parentheses ..
(+6x^2-30x+45x-225)=0
We get rid of parentheses
6x^2-30x+45x-225=0
We add all the numbers together, and all the variables
6x^2+15x-225=0
a = 6; b = 15; c = -225;
Δ = b2-4ac
Δ = 152-4·6·(-225)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-75}{2*6}=\frac{-90}{12} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+75}{2*6}=\frac{60}{12} =5 $
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