(2x+15)+(x-5)=(x-5)+(3x-12)

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Solution for (2x+15)+(x-5)=(x-5)+(3x-12) equation: 



(2x+15)+(x-5)=(x-5)+(3x-12)

We move all terms to the left:

(2x+15)+(x-5)-((x-5)+(3x-12))=0

We get rid of parentheses

2x+x-((x-5)+(3x-12))+15-5=0



We calculate terms in parentheses: -((x-5)+(3x-12)), so:

(x-5)+(3x-12)

We get rid of parentheses

x+3x-5-12

We add all the numbers together, and all the variables

4x-17

Back to the equation:

-(4x-17)



We add all the numbers together, and all the variables

3x-(4x-17)+10=0

We get rid of parentheses

3x-4x+17+10=0

We add all the numbers together, and all the variables

-1x+27=0

We move all terms containing x to the left, all other terms to the right

-x=-27

x=-27/-1

x=+27

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