(2x+15)=(3x-12)=x-5

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Solution for (2x+15)=(3x-12)=x-5 equation: 



(2x+15)=(3x-12)=x-5

We move all terms to the left:

(2x+15)-((3x-12))=0

We get rid of parentheses

2x-((3x-12))+15=0



We calculate terms in parentheses: -((3x-12)), so:

(3x-12)

We get rid of parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

2x-3x+12+15=0

We add all the numbers together, and all the variables

-1x+27=0

We move all terms containing x to the left, all other terms to the right

-x=-27

x=-27/-1

x=+27

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