(2x+16)(2x+12)=395

Solution for (2x+16)(2x+12)=395 equation:

(2x+16)(2x+12)=395

We move all terms to the left:

(2x+16)(2x+12)-(395)=0

We multiply parentheses ..

(+4x^2+24x+32x+192)-395=0

We get rid of parentheses

4x^2+24x+32x+192-395=0

We add all the numbers together, and all the variables

4x^2+56x-203=0

a = 4; b = 56; c = -203;
Δ = b2-4ac
Δ = 562-4·4·(-203)
Δ = 6384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6384}=\sqrt{16*399}=\sqrt{16}*\sqrt{399}=4\sqrt{399}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{399}}{2*4}=\frac{-56-4\sqrt{399}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{399}}{2*4}=\frac{-56+4\sqrt{399}}{8}
$