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(2x+16)(2x+32)=924
We move all terms to the left:
(2x+16)(2x+32)-(924)=0
We multiply parentheses ..
(+4x^2+64x+32x+512)-924=0
We get rid of parentheses
4x^2+64x+32x+512-924=0
We add all the numbers together, and all the variables
4x^2+96x-412=0
a = 4; b = 96; c = -412;
Δ = b2-4ac
Δ = 962-4·4·(-412)
Δ = 15808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15808}=\sqrt{64*247}=\sqrt{64}*\sqrt{247}=8\sqrt{247}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-8\sqrt{247}}{2*4}=\frac{-96-8\sqrt{247}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+8\sqrt{247}}{2*4}=\frac{-96+8\sqrt{247}}{8} $
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