(2x+16)+(4x+3)=35

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Solution for (2x+16)+(4x+3)=35 equation: 



(2x+16)+(4x+3)=35

We move all terms to the left:

(2x+16)+(4x+3)-(35)=0

We get rid of parentheses

2x+4x+16+3-35=0

We add all the numbers together, and all the variables

6x-16=0

We move all terms containing x to the left, all other terms to the right

6x=16

x=16/6

x=2+2/3

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