(2x+16)+(6x+2)+(4x-6)=180

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Solution for (2x+16)+(6x+2)+(4x-6)=180 equation: 



(2x+16)+(6x+2)+(4x-6)=180

We move all terms to the left:

(2x+16)+(6x+2)+(4x-6)-(180)=0

We get rid of parentheses

2x+6x+4x+16+2-6-180=0

We add all the numbers together, and all the variables

12x-168=0

We move all terms containing x to the left, all other terms to the right

12x=168

x=168/12

x=14

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