(2x+16)=(1x+12)+38

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Solution for (2x+16)=(1x+12)+38 equation: 



(2x+16)=(1x+12)+38

We move all terms to the left:

(2x+16)-((1x+12)+38)=0

We add all the numbers together, and all the variables

(2x+16)-((x+12)+38)=0

We get rid of parentheses

2x-((x+12)+38)+16=0



We calculate terms in parentheses: -((x+12)+38), so:

(x+12)+38

We get rid of parentheses

x+12+38

We add all the numbers together, and all the variables

x+50

Back to the equation:

-(x+50)



We get rid of parentheses

2x-x-50+16=0

We add all the numbers together, and all the variables

x-34=0

We move all terms containing x to the left, all other terms to the right

x=34

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