(2x+18)(2x+20)=1088

Solution for (2x+18)(2x+20)=1088 equation:

(2x+18)(2x+20)=1088

We move all terms to the left:

(2x+18)(2x+20)-(1088)=0

We multiply parentheses ..

(+4x^2+40x+36x+360)-1088=0

We get rid of parentheses

4x^2+40x+36x+360-1088=0

We add all the numbers together, and all the variables

4x^2+76x-728=0

a = 4; b = 76; c = -728;
Δ = b2-4ac
Δ = 762-4·4·(-728)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-132}{2*4}=\frac{-208}{8}
=-26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+132}{2*4}=\frac{56}{8}
=7
$