(2x+18)(3x-18)=0

Solution for (2x+18)(3x-18)=0 equation:

(2x+18)(3x-18)=0

We multiply parentheses ..

(+6x^2-36x+54x-324)=0

We get rid of parentheses

6x^2-36x+54x-324=0

We add all the numbers together, and all the variables

6x^2+18x-324=0

a = 6; b = 18; c = -324;
Δ = b2-4ac
Δ = 182-4·6·(-324)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-90}{2*6}=\frac{-108}{12}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+90}{2*6}=\frac{72}{12}
=6
$