(2x+18)+(32-2x)+(20x+10)=180

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Solution for (2x+18)+(32-2x)+(20x+10)=180 equation: 



(2x+18)+(32-2x)+(20x+10)=180

We move all terms to the left:

(2x+18)+(32-2x)+(20x+10)-(180)=0

We add all the numbers together, and all the variables

(2x+18)+(-2x+32)+(20x+10)-180=0

We get rid of parentheses

2x-2x+20x+18+32+10-180=0

We add all the numbers together, and all the variables

20x-120=0

We move all terms containing x to the left, all other terms to the right

20x=120

x=120/20

x=6

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