(2x+2)(2x+8)=20x

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Solution for (2x+2)(2x+8)=20x equation: 



(2x+2)(2x+8)=20x

We move all terms to the left:

(2x+2)(2x+8)-(20x)=0

We add all the numbers together, and all the variables

-20x+(2x+2)(2x+8)=0

We multiply parentheses ..

(+4x^2+16x+4x+16)-20x=0

We get rid of parentheses

4x^2+16x+4x-20x+16=0

We add all the numbers together, and all the variables

4x^2+16=0

a = 4; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·4·16
Δ = -256
Delta is less than zero, so there is no solution for the equation

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