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(2x+2)(3x-12)=90
We move all terms to the left:
(2x+2)(3x-12)-(90)=0
We multiply parentheses ..
(+6x^2-24x+6x-24)-90=0
We get rid of parentheses
6x^2-24x+6x-24-90=0
We add all the numbers together, and all the variables
6x^2-18x-114=0
a = 6; b = -18; c = -114;
Δ = b2-4ac
Δ = -182-4·6·(-114)
Δ = 3060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3060}=\sqrt{36*85}=\sqrt{36}*\sqrt{85}=6\sqrt{85}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{85}}{2*6}=\frac{18-6\sqrt{85}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{85}}{2*6}=\frac{18+6\sqrt{85}}{12} $
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