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(2x+2)(3x-63)=180
We move all terms to the left:
(2x+2)(3x-63)-(180)=0
We multiply parentheses ..
(+6x^2-126x+6x-126)-180=0
We get rid of parentheses
6x^2-126x+6x-126-180=0
We add all the numbers together, and all the variables
6x^2-120x-306=0
a = 6; b = -120; c = -306;
Δ = b2-4ac
Δ = -1202-4·6·(-306)
Δ = 21744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{21744}=\sqrt{144*151}=\sqrt{144}*\sqrt{151}=12\sqrt{151}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-12\sqrt{151}}{2*6}=\frac{120-12\sqrt{151}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+12\sqrt{151}}{2*6}=\frac{120+12\sqrt{151}}{12} $
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