(2x+2)(3x-63x)=180

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Solution for (2x+2)(3x-63x)=180 equation: 



(2x+2)(3x-63x)=180

We move all terms to the left:

(2x+2)(3x-63x)-(180)=0

We add all the numbers together, and all the variables

(2x+2)(-60x)-180=0

We multiply parentheses ..

(-120x^2-120x)-180=0

We get rid of parentheses

-120x^2-120x-180=0

a = -120; b = -120; c = -180;
Δ = b2-4ac
Δ = -1202-4·(-120)·(-180)
Δ = -72000
Delta is less than zero, so there is no solution for the equation

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