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(2x+2)(x+34)=180
We move all terms to the left:
(2x+2)(x+34)-(180)=0
We multiply parentheses ..
(+2x^2+68x+2x+68)-180=0
We get rid of parentheses
2x^2+68x+2x+68-180=0
We add all the numbers together, and all the variables
2x^2+70x-112=0
a = 2; b = 70; c = -112;
Δ = b2-4ac
Δ = 702-4·2·(-112)
Δ = 5796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5796}=\sqrt{36*161}=\sqrt{36}*\sqrt{161}=6\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-6\sqrt{161}}{2*2}=\frac{-70-6\sqrt{161}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+6\sqrt{161}}{2*2}=\frac{-70+6\sqrt{161}}{4} $
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