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(2x+2)+(3x-5)=5x-(3-2x)
We move all terms to the left:
(2x+2)+(3x-5)-(5x-(3-2x))=0
We add all the numbers together, and all the variables
(2x+2)+(3x-5)-(5x-(-2x+3))=0
We get rid of parentheses
2x+3x-(5x-(-2x+3))+2-5=0
We calculate terms in parentheses: -(5x-(-2x+3)), so:We add all the numbers together, and all the variables
5x-(-2x+3)
We get rid of parentheses
5x+2x-3
We add all the numbers together, and all the variables
7x-3
Back to the equation:
-(7x-3)
5x-(7x-3)-3=0
We get rid of parentheses
5x-7x+3-3=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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