(2x+2)-6=10-3(x-1)

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Solution for (2x+2)-6=10-3(x-1) equation: 



(2x+2)-6=10-3(x-1)

We move all terms to the left:

(2x+2)-6-(10-3(x-1))=0

We get rid of parentheses

2x-(10-3(x-1))+2-6=0



We calculate terms in parentheses: -(10-3(x-1)), so:

10-3(x-1)

determiningTheFunctionDomain
-3(x-1)+10

We multiply parentheses

-3x+3+10

We add all the numbers together, and all the variables

-3x+13

Back to the equation:

-(-3x+13)



We add all the numbers together, and all the variables

2x-(-3x+13)-4=0

We get rid of parentheses

2x+3x-13-4=0

We add all the numbers together, and all the variables

5x-17=0

We move all terms containing x to the left, all other terms to the right

5x=17

x=17/5

x=3+2/5

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