(2x+2)/3=(3x-1)/4

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Solution for (2x+2)/3=(3x-1)/4 equation: 



(2x+2)/3=(3x-1)/4

We move all terms to the left:

(2x+2)/3-((3x-1)/4)=0

We calculate fractions


2x/()+(-((3x-1)*3)/()=0



We calculate terms in parentheses: +(-((3x-1)*3)/(), so:

-((3x-1)*3)/(

We multiply all the terms by the denominator


-((3x-1)*3)



We calculate terms in parentheses: -((3x-1)*3), so:

(3x-1)*3

We multiply parentheses

9x-3

Back to the equation:

-(9x-3)



We get rid of parentheses

-9x+3

Back to the equation:

+(-9x+3)



We get rid of parentheses

2x/()-9x+3=0

We multiply all the terms by the denominator


2x-9x*()+3*()=0

We add all the numbers together, and all the variables

2x-9x*()=0

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