(2x+2)/8=(x+1)/4

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Solution for (2x+2)/8=(x+1)/4 equation: 


x in (-oo:+oo)

(2*x+2)/8 = (x+1)/4 // - (x+1)/4

(2*x+2)/8-((x+1)/4) = 0

(2*x+2)/8+(-1*(x+1))/4 = 0

(4*(2*x+2))/(4*8)+(-1*8*(x+1))/(4*8) = 0

4*(2*x+2)-1*8*(x+1) = 0

0 = 0

0/(4*8) = 0

0/(4*8) = 0 // * 4*8

0 = 0

x belongs to the empty set

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