(2x+2)=(3x+6)+(8x-16)

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Solution for (2x+2)=(3x+6)+(8x-16) equation: 



(2x+2)=(3x+6)+(8x-16)

We move all terms to the left:

(2x+2)-((3x+6)+(8x-16))=0

We get rid of parentheses

2x-((3x+6)+(8x-16))+2=0



We calculate terms in parentheses: -((3x+6)+(8x-16)), so:

(3x+6)+(8x-16)

We get rid of parentheses

3x+8x+6-16

We add all the numbers together, and all the variables

11x-10

Back to the equation:

-(11x-10)



We get rid of parentheses

2x-11x+10+2=0

We add all the numbers together, and all the variables

-9x+12=0

We move all terms containing x to the left, all other terms to the right

-9x=-12

x=-12/-9

x=1+1/3

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