(2x+2)x2=2(2x-2)

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Solution for (2x+2)x2=2(2x-2) equation: 



(2x+2)x2=2(2x-2)

We move all terms to the left:

(2x+2)x2-(2(2x-2))=0

We multiply parentheses

2x^3+2x^2-(2(2x-2))=0



We calculate terms in parentheses: -(2(2x-2)), so:

2(2x-2)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We do not support expression: x^3

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