(2x+20)(2x+25)=696

Solution for (2x+20)(2x+25)=696 equation:

(2x+20)(2x+25)=696

We move all terms to the left:

(2x+20)(2x+25)-(696)=0

We multiply parentheses ..

(+4x^2+50x+40x+500)-696=0

We get rid of parentheses

4x^2+50x+40x+500-696=0

We add all the numbers together, and all the variables

4x^2+90x-196=0

a = 4; b = 90; c = -196;
Δ = b2-4ac
Δ = 902-4·4·(-196)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11236}=106$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-106}{2*4}=\frac{-196}{8}
=-24+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+106}{2*4}=\frac{16}{8}
=2
$