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(2x+20)(2x+8)=540
We move all terms to the left:
(2x+20)(2x+8)-(540)=0
We multiply parentheses ..
(+4x^2+16x+40x+160)-540=0
We get rid of parentheses
4x^2+16x+40x+160-540=0
We add all the numbers together, and all the variables
4x^2+56x-380=0
a = 4; b = 56; c = -380;
Δ = b2-4ac
Δ = 562-4·4·(-380)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-96}{2*4}=\frac{-152}{8} =-19 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+96}{2*4}=\frac{40}{8} =5 $
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