(2x+20)=(5x+35)

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Solution for (2x+20)=(5x+35) equation: 



(2x+20)=(5x+35)

We move all terms to the left:

(2x+20)-((5x+35))=0

We get rid of parentheses

2x-((5x+35))+20=0



We calculate terms in parentheses: -((5x+35)), so:

(5x+35)

We get rid of parentheses

5x+35

Back to the equation:

-(5x+35)



We get rid of parentheses

2x-5x-35+20=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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