(2x+22)+(3x+3)+x=180

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Solution for (2x+22)+(3x+3)+x=180 equation: 



(2x+22)+(3x+3)+x=180

We move all terms to the left:

(2x+22)+(3x+3)+x-(180)=0

We add all the numbers together, and all the variables

x+(2x+22)+(3x+3)-180=0

We get rid of parentheses

x+2x+3x+22+3-180=0

We add all the numbers together, and all the variables

6x-155=0

We move all terms containing x to the left, all other terms to the right

6x=155

x=155/6

x=25+5/6

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